Y=-0.06x^2+10.1x+5=0

Solution for Y=-0.06x^2+10.1x+5=0 equation:

=-0.06Y^2+10.1Y+5=0

We move all terms to the left:

-(-0.06Y^2+10.1Y+5)=0

We get rid of parentheses

0.06Y^2-10.1Y-5=0

a = 0.06; b = -10.1; c = -5;
Δ = b2-4ac
Δ = -10.12-4·0.06·(-5)
Δ = 103.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.1)-\sqrt{103.21}}{2*0.06}=\frac{10.1-\sqrt{103.21}}{0.12}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.1)+\sqrt{103.21}}{2*0.06}=\frac{10.1+\sqrt{103.21}}{0.12}
$